Homework 01

  • LinearAlgebra (notebook version)

  • Homework 1: Linear Algebra

    Due date:

    Student Name:

    Exercise 1. Vectors

    a.- Show that given a vector v\vec{v} and a basis {ei}\{\vec{e_i}\} for i=1,,ni=1, \ldots ,n, there exists a unique linear combination of the basis elements that determines it. That is, if v=iviei\vec{v} = \sum_i v^i \vec{e_i} and v=iv~iei\vec{v} = \sum_i \tilde{v}^i \vec{e_i}, then vi=v~iv^i = \tilde{v}^i for all i=1,,ni=1, \ldots ,n.

    b.- Given two bases, {ei}\{\vec{e_i}\} and {e~i}\{\vec{\tilde{e}_i}\}, we can express the elements of one in terms of the other, e~j=iPjiei, ei=lRile~l.\vec{\tilde{e}j} = \sum_i P{j}{}^i \vec{e_i}, \;\;\;\;\;\; \vec{e_i} = \sum_l R_{i}{}^l \vec{\tilde{e}_l}.

    Show that Ril=Pi1lR_{i}{}^l = P^{-1}_{i}{}^l.

    c.- Let SS be a finite set, S=s1,s2,,snS = {s_1, s_2, \dots, s_n}. Find a basis for the vector space of all functions from SS to R\mathbb{R}. Determine the dimension of this space. Show that the dimension of VV is unique, meaning it does not depend on the basis used to define it.

    Exercise 2. Dual spaces

    If {ei}\{\vec{e}_i\} for i=1,,ni=1,\ldots,n is a basis of vector space VV, meaning a linearly independent set of vectors that span VV, we can define nn elements of VV^* (called co-vectors) by the relation

    θi(ej)=δi;j. \vec{\theta^i}(\vec{e}j) = \delta^i{;j}.

    That is, we define the action of θi\vec{\theta^i} on the {ej}\{\vec{e_j}\} as in the equation above and then extend its action to any element of VV by writing this element in the basis {ei}\{\vec{e}_i\} and using the fact that the action must be linear.

    It can be easily seen that any ρV\rho \in V' can be obtained as a linear combination of the co-vectors {θj}\{\vec{\theta^j}\}, j=1,,nj=1,\ldots,n and that these are linearly independent, therefore they form a basis and thus the dimension of VV' is also nn.

    a.- Show that VV^* is a vector space and that the θi{\vec{\theta^i}} indeed form a basis.

    b.- Show that if v=i=1nviei\vec{v} = \sum_{i=1}^{n} v^i \vec{e}_i then,

    vi=θi(v). v^i = \vec{\theta^i}(\vec{v}).

    c.- Let VV be the space of functions from a set with a finite number of elements, nn, to the real numbers. Let a basis be given by:

    ei(a):=(1if a is the i-th element0otherwise \vec{e}_i (a) := \left( \begin{array}{cl} 1 & \text{if } a \text{ is the } i\text{-th element} \\ 0 & \text{otherwise} \end{array} \right.

    Find the corresponding co-basis of its dual space.

    Exercise 3. Tensors

    Let ε\mathbf{\varepsilon} be a completely antisimmetric tensor with nn entries on a vector space of dimention nn, not identically zero, and {ei}\{\vec{e}_i\} any set of nn vectors.

    a.- Show that they form a bases if and only if

    ε(e1,,en)0. \mathbf{\varepsilon} (\vec{e_1},\ldots, \vec{e_n})\neq 0.

    b.- Let A\mathbf{ A} be any element of type (11){1 \choose 1},

    uV, vVA(u,v)R. \vec{u}\in V, \;\; \vec{ v}^*\in V^* \to \mathbf{A}(\vec{ u},\vec{v}^*)\in \mathbb{R}.

    This tensor is also a linear map from VVV \to V, indeed, A(u,)\mathbf{A}(\vec{ u},\cdot) is also a vector, since identifying VV with VV^{**}, is the unique vector that takes any covector ωV\vec{\omega} \in V^* and gives the number A(e,ω)\mathbf{A}(\vec{e},\mathbf{\omega}). Among the linear maps from VVV \to V there is the identity map. What is the identity map as an element of (11){1 \choose 1}?

    c.- Let {ei}\{\vec{e}_i\} be any base of VV and let ai\vec{ a}_i the vectors A(ei, )\vec{A}(\vec{e_i},\;\;), then,

    ε(a1,,an)=ε(A(e1, ),,A(en, )) \mathbf{\varepsilon}(\vec{a_1},\ldots,\vec{a_n})=\mathbf{\varepsilon}(\mathbf{A}(\vec{e_1},\;\;),\ldots ,\mathbf{A}(\vec{e_n},\;\;))

    is also totally antisymmetric in the {ei}\{\vec{e}_i\} and therefore,

    ε(A(e1, ),,A(en, ))ε(e1.,en). \mathbf {\varepsilon}(\mathbf{A}(\vec{e_1},\;\;),\ldots ,\mathbf{A}(\vec{e_n},\;\;)) \propto \mathbf{\varepsilon}(\vec{e_1}. \ldots, \vec{e_n}).

    The propertionality constant is called the determinant of the map A\mathbf{A},

    ε(A(e1, ),,A(en, ))=:det(A)ε(e1.,en). \mathbf{\varepsilon}(\mathbf{A}(\vec{e_1},\;\;),\ldots ,\mathbf{A}(\vec{e_n},\;\;)) =: \det(\mathbf{A}) \mathbf{\varepsilon}(\vec{e_1}. \ldots, \vec{e_n}).

    Show that this constant does not depends on the particular base used to define it. Thus it is a function from the linear maps of VV to the reals.

    d.- Let A\mathbf{A}, and B\mathbf{B} be to linear maps from VV into itself, then we can define the product of them as: AB(v):=A(B(v))\mathbf{A}\cdot \mathbf{B} (\vec{v}):=\mathbf{A}(\mathbf{B}(\vec{v})). Show that det(AB)=det(A)det(B)\det(\mathbf{A}\mathbf{B})=\det(\mathbf{A})\cdot \det(\mathbf{B}). Exercise 4. Quotient spaces

    Let VV be the vector space of continuos functions in R\mathbb{R} and let WW the subset of VV consisting on all the functions that vanish in the interval [0,1][0,1].

    a.- Show that WW is a vector subspace of VV.

    b.- Consider the quotient space V/WV/W, with which other space can we associate it?

    Exercise 5. Norms

    Let V=R2V = \mathbb{R}^2, and (x,y)=maxx,y||(x,y)|| = \max{|x|,|y|}. What is the norm induced in VV'? Exercise 6. Invariant Subspaces

    Find the invariant subspaces of the following linear maps on R2\mathbb{R}^2

    A1:=[0210] A_1 := \left[ \begin{array}{cc} 0 & 2 \\ 1 & 0 \end{array} \right] A2:=[1202] A_2 := \left[ \begin{array}{cc} 1 & 2 \\ 0 & 2 \end{array} \right]

    A3:=[1201] A_3 := \left[ \begin{array}{cc} 1 & 2 \\ 0 & 1 \end{array} \right]

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